2/5x^2-3/7x=o

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Solution for 2/5x^2-3/7x=o equation: 


x in (-oo:+oo)

(2/5)*x^2-((3/7)*x) = o // - o

(2/5)*x^2-o-((3/7)*x) = 0

(2/5)*x^2-o+(-3/7)*x = 0

2/5*x^2-o-3/7*x = 0

DELTA = (-3/7)^2-(2/5*4*(-o))

DELTA = 8/5*o+9/49

8/5*o+9/49 = 0

8/5*o+9/49 = 0 // - 9/49

8/5*o = -9/49 // : 8/5

o = -9/49/8/5

o = -45/392

DELTA = 0  <=>  t_1 = -45/392

x = 3/7/(2/5*2) i o = -45/392

x = 15/28 i o = -45/392

( x = ((8/5*o+9/49)^(1/2)+3/7)/(2/5*2) or x = (3/7-(8/5*o+9/49)^(1/2))/(2/5*2) ) i o > -45/392

( x = 5/4*((8/5*o+9/49)^(1/2)+3/7) or x = 5/4*(3/7-(8/5*o+9/49)^(1/2)) ) i o > -45/392

o+45/392 > 0

o+45/392 > 0 // - 45/392

o > -45/392

x in { 15/28, 5/4*((8/5*o+9/49)^(1/2)+3/7), 5/4*(3/7-(8/5*o+9/49)^(1/2)) }

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